Question:

A steel ring of radius r and cross sectional area 'A' is fitted on to a wooden disc of radius R (R > r). If the Young's modulus be Y, then what is the force with which steel ring is expanded?

Updated On: Oct 4, 2024
  • \(\frac{AYR}{r}\)
  • \(\frac{AR}{Y_r}\)
  • \(\frac{A}{Y}(\frac{r}{R-r})\)
  • \(AY(\frac{R-r}{R})\)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

The correct option is (D): \(AY(\frac{R-r}{R})\)
Was this answer helpful?
0
0

Top Questions on mechanical properties of solids

View More Questions