Question:

A starts 3 min after B for a place 4.5 km distant B, on reaching his destination, immediately returns and after walking a km meets A. if A can walk 1 km in 18 minutes, then what is B's speed?

Updated On: Sep 25, 2024
  • 5 kmph
  • 4 kmph
  • 6 kmph
  • 3.5 kmph
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The Correct Option is A

Solution and Explanation

The correct option is (A): 5
Explation: Explanation:
Let B's speed be \(x\) km/hr and A's speed = \(\frac{60}{18}=\frac{10}{3}\) km/hr
Distance covered by B in 3 minutes = \(\frac{x}{20}\) km
Now, time taken by A to travel 3.5 km = Time taken by B to travel 5.5 km - 3 minutes
\(= 3.5 \times\frac{3}{10} =\frac{5.5}{x}-\frac{3}{60}\)
\(=\) 1.05 +0.05 =\(\frac{5.5}{x}\)
\(=\) \(x\)=\(\frac{5.5}{1.1}\)=5 km/hr
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