Question:

A square dart board has four dark circular regions of radius 3 inches as shown in the design above. Each point on the dart board is equally likely to be hit by a dart that hits the board. What is the probability that a dart that hits the board will hit one of the circular regions?

Show Hint

In geometric probability, the formula is always \( P = \frac{\text{Favorable Area}}{\text{Total Area}} \). Make sure you calculate the correct areas and then simplify the resulting fraction.
Updated On: Oct 4, 2025
  • \( \frac{\pi}{16} \)
  • \( \frac{\pi}{48} \)
  • \( \frac{\pi}{64} \)
  • \( \frac{1}{3} \)
  • \( \frac{1}{4} \)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
This is a geometric probability problem. The probability of hitting a certain region is the ratio of the area of the desired region (the "favorable" area) to the total area of the entire space (the "sample space" area).
Step 2: Key Formula or Approach:
1. Calculate the total area of the dart board (a square). Area of square = side\(^2\). 2. Calculate the area of one circular region. Area of circle = \(\pi r^2\). 3. Calculate the total area of the four circular regions. 4. The probability is the ratio: \( P(\text{hit circle}) = \frac{\text{Total area of circles}}{\text{Area of square}} \).
Step 3: Detailed Explanation:
1. Total Area (Square): From the diagram, the side length of the square dart board is 24 inches. \[ \text{Area}_{\text{square}} = (24 \text{ in})^2 = 576 \text{ in}^2 \] 2. Area of one Circle: The radius (\(r\)) of each circular region is 3 inches. \[ \text{Area}_{\text{one circle}} = \pi r^2 = \pi (3 \text{ in})^2 = 9\pi \text{ in}^2 \] 3. Total Favorable Area (Four Circles): There are four identical circular regions. \[ \text{Area}_{\text{four circles}} = 4 \times \text{Area}_{\text{one circle}} = 4 \times 9\pi = 36\pi \text{ in}^2 \] 4. Calculate the Probability: \[ P(\text{hit circle}) = \frac{\text{Area}_{\text{four circles}}}{\text{Area}_{\text{square}}} = \frac{36\pi}{576} \] Now, we simplify the fraction \( \frac{36}{576} \). We can divide both by common factors. Both are divisible by 36. \( 576 \div 36 \): \( 576 = 10 \times 36 + 216 \). \( 216 = 6 \times 36 \). So \( 576 = 16 \times 36 \). \[ \frac{36}{576} = \frac{1 \times 36}{16 \times 36} = \frac{1}{16} \] Therefore, the probability is: \[ P(\text{hit circle}) = \frac{\pi}{16} \] Step 4: Final Answer:
The probability of hitting one of the circular regions is \( \frac{\pi}{16} \).
Was this answer helpful?
0
0

Questions Asked in GRE exam

View More Questions