Question:

A solid sphere of uniform density and radius 4 units is located with its centre at the origin O of coordinates. Two spheres of equal radii 1 unit, with their centres at $\lambda$ (-2,0,0) and B (2,0,0) respectively, are taken out of the solid leaving behind spherical cavities as shown in figure. Then,

Updated On: Jul 14, 2022
  • the gravitational field due to this object at the origin is zero
  • the gravitational field at the point B (2, 0, 0) is zero
  • the gravitational potential is the same at all points of circle $y^2 + z^2 = 36$
  • the gravitational potential is the same at all points on the circle $y^2 + z^2 =4$
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The Correct Option is D

Solution and Explanation

The gravitational field is zero at the centre of a solid sphere. The small spheres can be considered as negative mass m located at A and B. The gravitational field due to these masses at O is equal and opposite. Hence, the resultant field at O is zero (c and d ) $\rightarrow$ are correct because plane of these circles isy-z, i.e. perpendicular to x-axis i.e. potential at any point on these two circles will be equal due to the positive mass M and negative masses -m and -m.
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].