Question:

A solid sphere of radius \( R \) carries a uniform volume charge density \( \rho \). The magnitude of electric field inside the sphere at a distance \( r \) from the centre is

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The electric field inside a uniformly charged sphere increases linearly with \( r \) and depends on the charge density.
Updated On: Jan 12, 2026
  • \( \frac{r \rho}{3 \epsilon_0} \)
  • \( \frac{r^2 \rho}{6 \epsilon_0} \)
  • \( \frac{r^2 \rho}{\epsilon_0} \)
  • \( \frac{r^2 \rho}{3 \epsilon_0} \)
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The Correct Option is D

Solution and Explanation

Step 1: Electric Field Inside a Charged Sphere.
For a uniformly charged sphere, the electric field inside the sphere at a distance \( r \) from the center is given by: \[ E = \frac{r^2 \rho}{3 \epsilon_0} \] where \( \rho \) is the charge density and \( \epsilon_0 \) is the permittivity of free space.
Step 2: Conclusion.
The correct answer is (D), \( \frac{r^2 \rho}{3 \epsilon_0} \).
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