Question:

A long solenoid is formed by winding 70 turns cm-1. If 2.0 A current flows, then the magnetic field produced inside the solenoid is _________ (µ0 = 4π × 10-7 TmA-1)

Updated On: Jun 23, 2024
  • 1232 × 10–4T
  • 176 × 10–4T
  • 352 × 10–4T
  • 88 × 10–4T
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The Correct Option is B

Solution and Explanation

To find the magnetic field inside a solenoid, we can use the formula for the magnetic field inside an ideal solenoid:
\(B = \mu_0 n I\)
Given:
Number of turns per cm = 70turns/cm,
Current I = 2A.
Convert the number of turns per cm to turns per meter (since the SI unit of length is meter):
\(n = 70 \, \text{turns/cm} \times 100 \, \text{cm/m} = 7000 \, \text{turns/m}\)

\(B = \mu_0 n I\)
\(B = (4\pi \times 10^{-7} \, \text{T m/A}) \times (7000 \, \text{turns/m}) \times (2 \, \text{A})\)
\(B = 4\pi \times 10^{-7} \times 7000 \times 2\)
\(B = 4\pi \times 14000 \times 10^{-7}\)
\(B = 56000\pi \times 10^{-7}\)
\(B = 5.6\pi \times 10^{-3} \, \text{T}\)
\(B = 5.6 \times 3.14 \times 10^{-3} \, \text{T}\)
\(B = 17.584 \times 10^{-3} \, \text{T}\)
\(B = 0.0176 \, \text{T}\)
\(B = 176 \times 10^{-4} \text{T}\)

So, the correct option is (B): \(176 \times 10^{-4} \text{T}\)

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