For a step-index fiber surrounded by a medium of refractive index \(n_s\), the NA is
\[
\mathrm{NA}=\sqrt{n_1^2-n_s^2},
\]
where \(n_1\) is the core index and \(n_s\) is the surrounding medium’s index (here water, since cladding is removed). Thus
\[
\mathrm{NA}=\sqrt{1.47^2-1.33^2}
=\sqrt{2.1609-1.7689}
=\sqrt{0.3920}
=0.626 \;.
\]
Final Answer: 0.626