Question:

A short- circuited coil is placed in a time varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of turns were to be quadrupled (four times) and wire radius halved, the electrical power dissipated would be

Updated On: Sep 6, 2023
  • halved
  • the same
  • doubled
  • quadrupled
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The Correct Option is B

Solution and Explanation

$P =\frac{\varepsilon^{2}}{ R }$ where, $\varepsilon=$ inducedemf $=-\frac{ d \phi}{ d t}$ $\phi= N B A$ $\varepsilon= N A \frac{ d }{ d t}$ also, $R \propto \frac{1}{ r ^{2}}$ where, $R=$ resistance and $r=$ radius of wire $P \propto \frac{ N ^{2} r ^{2}}{1^{2}}$ $\frac{ P _{1}}{ P _{2}}= 1$ $P _{1}= P _{2}$ This means if the number of turns were quadrupled and the wire radius halved, the electrical power dissipated would be remains same.
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Top Questions on Electromagnetic induction

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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter