A short- circuited coil is placed in a time varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of turns were to be quadrupled (four times) and wire radius halved, the electrical power dissipated would be
Updated On: Sep 6, 2023
halved
the same
doubled
quadrupled
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The Correct Option isB
Solution and Explanation
$P =\frac{\varepsilon^{2}}{ R }$
where, $\varepsilon=$ inducedemf $=-\frac{ d \phi}{ d t}$$\phi= N B A$$\varepsilon= N A \frac{ d }{ d t}$
also, $R \propto \frac{1}{ r ^{2}}$
where, $R=$ resistance and $r=$ radius of wire $P \propto \frac{ N ^{2} r ^{2}}{1^{2}}$$\frac{ P _{1}}{ P _{2}}= 1$$P _{1}= P _{2}$
This means if the number of turns were quadrupled and the wire radius halved, the electrical power dissipated would be remains same.
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
When we place the conductor in a changing magnetic field.
When the conductor constantly moves in a stationary field.