Question:

A satellite in force free space sweeps stationary interplanetary dust at a rate of $ dM/dt = \alpha v $ , where M is mass and v is the speed of satellite and $\alpha$ is a constant. The acceleration of satellite is

Updated On: May 25, 2022
  • $ \frac{- \alpha v^2}{2M}$
  • $- \alpha v^2$
  • $ \frac{- 2\alpha v^2}{M}$
  • $ \frac{- \alpha v^2}{M}$
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The Correct Option is D

Solution and Explanation

Rate of change of mass $ \frac{dM}{dt} = \alpha v $.
Retarding force = Rate of change of momentum
= Velocity x Rate of change in mass = $ -v \times \frac{dM}{dt}$
$ = - v \times \alpha v = - \alpha v^2 .$ (Minus sign of v due to deceleration)
Therefore Acceleration $= \frac{-\alpha v^2}{ M}$.
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  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].