A's age is $\frac{1}{6}$ th of B's age. B's age will be twice of C's age after 10 years. If C's eighth birthday was celebrated two years ago, then the present age of A must be

Question

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The correct option is (A): 5 years Let Age of B = $6x$  years, and age of  A = $x$  years and C' present age = 10 years So, Acc. to ques: ⇒  $6x + 10 = 2 × (10 + 10)$ ⇒ $6x = 30$ ⇒ $x=5$ $\therefore$  Present age of A= 5 years.

Answer

<div>5 years</div>

Answer

<div>10 years</div>

Answer

<div>15 years</div>

Answer

<div>20 years</div>

A's age is \(\frac{1}{6}\)^th of B's age. B's age will be twice of C's age after 10 years. If C's eighth birthday was celebrated two years ago, then the present age of A must be

The Correct Option is A

Solution and Explanation

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A's age is \(\frac{1}{6}\)th of B's age. B's age will be twice of C's age after 10 years. If C's eighth birthday was celebrated two years ago, then the present age of A must be

The Correct Option is A

Solution and Explanation

Top Questions on Equations

Questions Asked in MAT exam

A's age is \(\frac{1}{6}\)^th of B's age. B's age will be twice of C's age after 10 years. If C's eighth birthday was celebrated two years ago, then the present age of A must be