Question

A runs 1\(\frac{2}{3}\) times as fast as B. If A gives B a start of 3 80 in. How far must the winning post be so that A and B reach it at the same time?

• A. 300 m
• B. 200 m
• C. 270 m
• D. 160 m

Answer 1

The Correct Option is B

Ratio of the speeds of A and B \(=\frac{5}{3}:1=\frac{5}{3}\) 
Thus, in race of 5 m, A gains 2 m over B.
2 m are gained by A in a race of 5 m.
80 m will be gained by A in race of \((\frac{5}{2\times80})\):
=200 meters
So,
Winning post is 200 m away from the starting point.
So the correct option is (B)