
(i) Surface area of sphere = \(4\pi r^2\)
(ii) Height of cylinder = r + r = 2r
Radius of cylinder = r
CSA of cylinder = \(2\pi rh = 2\pi r (2r)\)
\(= 4\pi r^2\)
(iii) The ratio of the areas obtained in (i) and (ii) is:
\(\frac{4\pi r^2}{4\pi r^2} = \frac{1}{1}\)
Therefore, the ratio between these two surface areas is 1:1.
एक गोलाची त्रिज्या 7 सेमी असेल तर त्याचे वर्तुळ क्षेत्रफळ काय असेल?
(i) The kind of person the doctor is (money, possessions)
(ii) The kind of person he wants to be (appearance, ambition)
ABCD is a quadrilateral in which AD = BC and ∠ DAB = ∠ CBA (see Fig. 7.17). Prove that
(i) ∆ ABD ≅ ∆ BAC
(ii) BD = AC
(iii) ∠ ABD = ∠ BAC.
