(i) Surface area of sphere = \(4\pi r^2\)
(ii) Height of cylinder = r + r = 2r
Radius of cylinder = r
CSA of cylinder = \(2\pi rh = 2\pi r (2r)\)
\(= 4\pi r^2\)
(iii) The ratio of the areas obtained in (i) and (ii) is:
\(\frac{4\pi r^2}{4\pi r^2} = \frac{1}{1}\)
Therefore, the ratio between these two surface areas is 1:1.
In Fig. 9.26, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find ∠ BAC.