Question

A resistor of \( 10 \, \Omega \) is connected in series with a 12 V battery. What is the current flowing through the resistor?

• A. \( 0.5 \, \text{A} \)
• B. \( 1.2 \, \text{A} \)
• C. \( 0.8 \, \text{A} \)
• D. \( 2.5 \, \text{A} \)

Hint:

Ohm's law relates voltage, current, and resistance by \( I = \frac{V}{R} \).

Answer 1

The Correct Option is A

Step 1: Use Ohm's Law Ohm's Law states that the current \( I \) through a resistor is given by: \[ I = \frac{V}{R} \] where: - \( V \) is the voltage across the resistor, - \( R \) is the resistance. Step 2: Substitute the given values Given: - Voltage \( V = 12 \, \text{V} \), - Resistance \( R = 10 \, \Omega \). Substitute these values into the formula: \[ I = \frac{12}{10} = 1.2 \, \text{A} \] Answer: Therefore, the current flowing through the resistor is \( 1.2 \, \text{A} \). So, the correct answer is option (2).