Step 1: Analyzing the options.
- (A) This statement misinterprets the meaning of the P-value. The P-value does not refer to repeating the study 100 times with the same probability.
- (B) This is a common misconception. The P-value is not the probability that the null hypothesis is true, but rather the probability of obtaining a result at least as extreme as the one observed.
- (C) This is correct. The P-value of 0.02 means that the probability of obtaining an F-statistic of 6.04 or greater, under the assumption that there is no difference between habitats, is 0.02.
- (D) The P-value being less than 0.05 only tells us that there is evidence to reject the null hypothesis, but it does not imply a "very large difference."
Step 2: Conclusion.
The correct answer is (C), as the P-value represents the probability of obtaining an F-statistic as extreme as the observed value under the null hypothesis.
Final Answer: (C) the probability that an F-statistic with a value of 6.04 or greater falls within the F-distribution for 1 and 18 degrees of freedom is 0.02.
From a set of data involving four "tropical feed stuffs A, B, C and D", tried on 20 chicks, the following information was extracted:
\[ \begin{array}{|l|c|c|} \hline \textbf{Source of variation} & \textbf{Sum of squares} & \textbf{Degrees of freedom} \\ \hline \text{Treatment} & 26000 & 3 \\ \text{Error} & 11500 & 16 \\ \hline \end{array} \]
All the 20 chicks were treated alike, except for the feeding treatment, and each feeding treatment was given to 5 chicks. Then, the critical difference between any two means is:
It is given that there are six treatments and four blocks,
\[ \begin{array}{|l|cccccc|} \hline \textbf{Treatment totals} & T_1 & T_2 & T_3 & T_4 & T_5 & T_6 \\ & 63 & 65 & 57 & 64 & 65 & 66 \\ \hline \textbf{Block totals} & B_1 & B_2 & B_3 & B_4 & & \\ & 90 & 85 & 106 & 98 & & \\ \hline \end{array} \]
and that \( G = \sum_i \sum_j y_{ij} = 380 \), then the sum of squares due to treatment is:
For the given ANOVA table:
\[ \begin{array}{|l|c|c|} \hline \textbf{Source of variation} & \textbf{Sum of squares} & \textbf{Degrees of freedom} \\ \hline \text{Service station} & 6810 & 9 \\ \text{Rating} & 400 & 4 \\ \text{Total} & 9948 & 49 \\ \hline \end{array} \]
The test statistic to test that there is no significant difference between the service stations is:
Eight students (P, Q, R, S, T, U, V, and W) are playing musical chairs. The figure indicates their order of position at the start of the game. They play the game by moving forward in a circle in the clockwise direction.
After the 1st round, the 4th student behind P leaves the game.
After the 2nd round, the 5th student behind Q leaves the game.
After the 3rd round, the 3rd student behind V leaves the game.
After the 4th round, the 4th student behind U leaves the game.
Who all are left in the game after the 4th round?

Here are two analogous groups, Group-I and Group-II, that list words in their decreasing order of intensity. Identify the missing word in Group-II.
Abuse \( \rightarrow \) Insult \( \rightarrow \) Ridicule
__________ \( \rightarrow \) Praise \( \rightarrow \) Appreciate
The 12 musical notes are given as \( C, C^\#, D, D^\#, E, F, F^\#, G, G^\#, A, A^\#, B \). Frequency of each note is \( \sqrt[12]{2} \) times the frequency of the previous note. If the frequency of the note C is 130.8 Hz, then the ratio of frequencies of notes F# and C is: