Question:

A research satellite of mass 200 kg circles the earth in an orbit of average radius $\frac{3R}{2}$ where R is the radius of earth. Assuming the gravitatioaal pull on a mass of 1 kg on the earth's surface to be 10 N, the puII on the sateIlite will be

Updated On: Apr 7, 2024
  • 880 N
  • 889 N
  • 885 N
  • 892 N
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The Correct Option is B

Solution and Explanation

On earth,$ mg= 10\, or\, 1 \times g = 10 \Rightarrow g = 10\, ms^{-2}$ Now, $\hspace10mm g' = g\frac{R^2}{r^2} = 10 \times \frac{R^2}{(3R/2)^2}=\frac{40}{9}$ Pull on satellite = m' g' $\hspace25mm = 200 \times \frac{40}{9} = 889\, N$
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].