Question

A random variable \( X \) has the probability distribution \[ P(X) = \{ 0.15, 0.23, 0.12, 0.10, 0.20, 0.07, 0.06, 0.08 \} \] For the events \( E = \{ X \text{ is a prime number} \} \) and \( F = \{ X<4 \} \), then \( P(E \cup F) \) is

• A. 0.50
• B. 0.77
• C. 0.35
• D. 0.87

Hint:

For the union of two events, use \( P(E \cup F) = P(E) + P(F) - P(E \cap F) \).

Answer 1

The Correct Option is B

The union of events \( E \) and \( F \) is calculated by adding the probabilities of each event and subtracting the intersection.
Final Answer: \[ \boxed{0.77} \]