Question:

A pressure of \( 500 \, \text{kPa} \) applied to \( 2 \, \text{m}^3 \) of liquid results in a volume change of \( 0.004 \, \text{m}^3 \). The bulk modulus in MPa is:

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Bulk modulus measures a fluid’s resistance to compression; higher values indicate less compressibility.
Updated On: Dec 28, 2024
  • 2.5
  • 25
  • 250
  • 2500
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The Correct Option is B

Solution and Explanation

The bulk modulus (\( K \)) is calculated using:

\( K = \frac{\Delta P}{\Delta V / V} \)

Substituting \( \Delta P = 500 \, \text{kPa}, \, V = 2 \, \text{m}^3, \) and \( \Delta V = 0.004 \, \text{m}^3 \), we find:

\( K = \frac{500}{0.004 / 2} = 25 \, \text{MPa}. \)

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