A precipitate is formed if the ionic product is __________?
Greater than the solubility product
Lesser than the solubility product
Equal to solubility product
Independent of solubility product
The correct option is (A): Greater than the solubility product
Calculate the Reynold’s number for a liquid of density 1 g/cm3, viscosity 8 x 10-4 Pa.s flowing at 0.5 m/s through a pipe of diameter 4 cm?
Which of the following statement is true for aqueous solution of 0.1 M urea, 0.2 M glucose nad 0.3 M sucrose
The molar conductivities at infinite dilution for Na2SO4,K2S04,KCl, HCl and HCOONa at 300K are 260, 308, 150, 426, and 105 S cm2 mol-1, respectively. What will be A+m for formic acid in the same unit?
Electrophilic halogenation of phenol does not require catalyst because
Law of Chemical Equilibrium states that at a constant temperature, the rate of a chemical reaction is directly proportional to the product of the molar concentrations of the reactants each raised to a power equal to the corresponding stoichiometric coefficients as represented by the balanced chemical equation.
Let us consider a general reversible reaction;
A+B ↔ C+D
After some time, there is a reduction in reactants A and B and an accumulation of the products C and D. As a result, the rate of the forward reaction decreases and that of backward reaction increases.
Eventually, the two reactions occur at the same rate and a state of equilibrium is attained.
By applying the Law of Mass Action;
The rate of forward reaction;
Rf = Kf [A]a [B]b
The rate of backward reaction;
Rb = Kb [C]c [D]d
Where,
[A], [B], [C] and [D] are the concentrations of A, B, C and D at equilibrium respectively.
a, b, c, and d are the stoichiometric coefficients of A, B, C and D respectively.
Kf and Kb are the rate constants of forward and backward reactions.
However, at equilibrium,
Rate of forward reaction = Rate of backward reaction.
Kc is called the equilibrium constant expressed in terms of molar concentrations.
The above equation is known as the equation of Law of Chemical Equilibrium.