Question:

A polyester fabric of 150 cm width and areal density of 300 g/m\(^2\) is printed at a speed of 60 m/min. The solid content of the print paste is 50%. After printing and drying, the areal density of the printed fabric becomes 400 g/m\(^2\). The consumption (kg/h) of the print paste (in integer) is ________________.

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Print paste consumption depends on change in fabric areal density and fabric area processed per minute.
Updated On: Dec 2, 2025
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Correct Answer: 1075

Solution and Explanation

Increase in areal density due to paste solids: \[ 400 - 300 = 100\ \text{g/m}^2 \] Since solids = 50%, the paste applied per m\(^2\) is: \[ \frac{100}{0.5} = 200\ \text{g/m}^2 \] Fabric printed per minute: \[ \text{Area} = 1.5\ \text{m} \times 60\ \text{m} = 90\ \text{m}^2/\text{min} \] Paste required per minute: \[ 90 \times 200 = 18000\ \text{g/min} = 18\ \text{kg/min} \] Paste required per hour: \[ 18 \times 60 = 1080\ \text{kg/h} \] Rounded to range: 1075 to 1085 kg/h. Final Answer: 1075–1085 kg/h
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