9 : 4
2 : 9
9 : 2
4 : 9
Intensity I=\(\frac{p}{\pi r^2}\)
Also 1 \(\propto\) \(\frac{1}{r^2}\)=\(\frac{I_1}{I_2}\)=\(\bigg(\frac{r_2}{r_1}\bigg)^2\)
we have r1=2m, r2= 3m
substituting w have \(\frac{I_1}{I_2}\)=\(\bigg(\frac{3}{2}\bigg)^2\)=\(\frac{9}{4}\)
i.e, 9:4
Therefore, the correct option is (A): 9 : 4
Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen?