Question:

A point \(P\) on the wheel of radius \(R\) is initially in contact with the ground. When the wheel rolls forward half a revolution, the displacement of the point \(P\) is:

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The displacement of a point on a rolling wheel combines both translational and rotational motion. For half a revolution, this results in the formula \( R \sqrt{\pi^2 + 4} \).
Updated On: May 14, 2025
  • \( R \)
  • \( \pi R \)
  • \( R \sqrt{\pi^2 + 4} \)
  • \( R \sqrt{\pi + 4} \)
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The Correct Option is C

Solution and Explanation

The displacement of the point \(P\) is derived by considering the combined effect of the wheel's forward motion and rotation. The total displacement when the wheel rolls half a revolution is \( R \sqrt{\pi^2 + 4} \), as derived from the geometric relation between the point's path and the wheel's radius.
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