Question:
A point mass is placed inside a thin spherical shell of radius $ H $ and mass $ M $ at a distance $R/2$ from the centre of the shell. The gravitational force exerted by the shell on the point mass is.
A point mass is placed inside a thin spherical shell of radius $ H $ and mass $ M $ at a distance $R/2$ from the centre of the shell. The gravitational force exerted by the shell on the point mass is.
Updated On: Aug 15, 2022
- $\frac{G M}{-2 R^{2}}$
- $\frac{G M}{2 R^{2}}$
- zero
- $ \frac{GM}{4R^{2}} $
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The Correct Option is C
Solution and Explanation
Intensity due to spherical shell inside the surface $I=0$
Gravitational field $F=\text{Im}$
$F=0 \times m=0$
$ F=0$
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Concepts Used:
Gravitation
In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
Newton’s Law of Gravitation
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
- F ∝ (M1M2) . . . . (1)
- (F ∝ 1/r2) . . . . (2)
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].