A point charge \( q \) is rotated along a circle in the electric field generated by another point charge \( Q \). The work done by the electric field on the rotating charge in one complete revolution is:
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In circular motion, if the electric field force is perpendicular to the displacement, no work is done on the charge.
zero if the charge \( Q \) is at the centre and nonzero otherwise
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The Correct Option isA
Solution and Explanation
Step 1: Electric field and work done.
The work done by an electric field on a charge is given by:
\[
W = \vec{F} \cdot \vec{d}
\]
where \( F \) is the force and \( d \) is the displacement. In a circular motion, the force is always perpendicular to the displacement, implying no work is done.
Step 2: Conclusion.
Since the electric field does no work on a charge moving along a circle with a perpendicular direction of motion, the total work done is zero.
Final Answer:
\[
\boxed{0}
\]