Question:

A planet revolves in an elliptical orbit around the sun. The semi-major and semi-minor axes are \( a \) and \( b \). Then the square of the time period, \( T \), is directly proportional to:

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Kepler's third law connects the time period of a planet's orbit to the cube of the semi-major axis of its orbit.
Updated On: Jan 12, 2026
  • \( a^3 \)
  • \( b^3 \)
  • \( \frac{(a + b)^3}{2} \)
  • \( \frac{(a - b)^3}{2} \)
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The Correct Option is A

Solution and Explanation

Kepler's third law states that the square of the orbital period \( T \) of a planet is directly proportional to the cube of the semi-major axis \( a \) of its orbit. Thus, \( T^2 \propto a^3 \).
Final Answer: \[ \boxed{a^3} \]
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