Question:

A planet moves around the sun (mass = $M_{s}$ ) in an elliptical orbit such that its minimum and maximum distance from the sun are $r$ and $R$ respectively. The period of revolution of this planet around the sun is

Updated On: Jul 5, 2022
  • $T=\pi \sqrt{\frac{\left(r + R\right)^{3}}{2 G M_{s}}}$
  • $T=\pi \sqrt{\frac{\left(r + R\right)^{3}}{3 G M_{s}}}$
  • $T=\pi \sqrt{\frac{\left(r + R\right)^{3}}{G M_{s}}}$
  • $T=\pi \sqrt{\frac{2 \left(r + R\right)^{3}}{G M_{s}}}$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

The length of the semi-major axis of the elliptical orbit of the planet is $a=\frac{r + R}{2}$ If we assume that there is a hypothetical planet which moves around the sun in a circular orbit of radius $r_{0}=\frac{r + R}{2}$ , then the time period of this hypothetical planet and our given planet will be same. The time period of a planet around the sun in circular orbit is $T=2\pi \sqrt{\frac{\left(r^{3}\right)_{0}}{G M_{s}}}=2\pi \sqrt{\frac{\left(\frac{r + R}{2}\right)^{3}}{G M_{s}}}$ $T=\pi \sqrt{\frac{\left(r + R\right)^{3}}{2 G M_{s}}}$
Was this answer helpful?
0
0

Top Questions on Gravitation

View More Questions

Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].