Let the original times be \(T\) hours and original speed be \(x\) km/h
\(\frac{1500}{x}=T\)
\(\frac{1500}{x+250}=T-\frac{30}{60}\)
Solving equations (i) and (ii), we get
Speed of plane \(=x=750\) or \(-1000\) (not possible)
\(\therefore\) \(x=750\) km/h
The correct option is (B)