Question:

A person sold two different items at the same price. He made 10\% profit in one item, and 10\% loss in the other item. In selling these two items, the person made a total of:

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When equal selling prices are given, the overall result depends on the cost price difference and the percentage profit or loss for each item.
Updated On: Jan 23, 2025
  • 1\% profit
  • 2\% profit
  • 1\% loss
  • 2\% loss
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The Correct Option is C

Solution and Explanation

Let the selling price (SP) of each item be 100units 100 \, \text{units} . Step 1: Calculate the cost price (CP) for each item. For the first item, there is a 10% 10\% profit: CP1=SP11.1=1001.190.91units. \text{CP}_1 = \frac{\text{SP}_1}{1.1} = \frac{100}{1.1} \approx 90.91 \, \text{units}. For the second item, there is a 10% 10\% loss: CP2=SP20.9=1000.9111.11units. \text{CP}_2 = \frac{\text{SP}_2}{0.9} = \frac{100}{0.9} \approx 111.11 \, \text{units}. Step 2: Compute the total cost price and total selling price. Total CP=CP1+CP2=90.91+111.11=202.02units. \text{Total CP} = \text{CP}_1 + \text{CP}_2 = 90.91 + 111.11 = 202.02 \, \text{units}. Total SP=100+100=200units. \text{Total SP} = 100 + 100 = 200 \, \text{units}. Step 3: Determine the overall profit or loss. Loss=Total CPTotal SP=202.02200=2.02units. \text{Loss} = \text{Total CP} - \text{Total SP} = 202.02 - 200 = 2.02 \, \text{units}. Loss percentage=LossTotal CP×100=2.02202.02×1001%. \text{Loss percentage} = \frac{\text{Loss}}{\text{Total CP}} \times 100 = \frac{2.02}{202.02} \times 100 \approx 1\%. Final Answer: 1% loss \boxed{\text{1\% loss}}
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