Question:
A person goes in for an examination in which there are four papers with a maximum of m marks from each paper. The number of ways in which one can get 2m marks is
A person goes in for an examination in which there are four papers with a maximum of m marks from each paper. The number of ways in which one can get 2m marks is
Updated On: Mar 18, 2024
- \(\frac{1}{3}(m+1)(2m^2+4m+1)\)
- \(\frac{1}{3}(m+1)(2m^2+4m+2)\)
- \(\frac{1}{3}(m+1)(2m^2+4m+3)\)
- \(^{2m+3}C_3\)
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The Correct Option is C
Solution and Explanation
The correct answer is(C): \(\frac{1}{3}(m+1)(2m^2+4m+3)\)
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