Question:
A particle of mass \(m\) is executing oscillation about the origin on X-axis. Its potential energy is \(V(x) = K|x|^3\). Where \(K\) is a positive constant. If the amplitude of oscillation is \(a\), then its time period \(T\) is proportional to
A particle of mass \(m\) is executing oscillation about the origin on X-axis. Its potential energy is \(V(x) = K|x|^3\). Where \(K\) is a positive constant. If the amplitude of oscillation is \(a\), then its time period \(T\) is proportional to
Updated On: Jun 21, 2024
- \(\frac {1}{\sqrt a}\)
- \(a\)
- \(\sqrt a\)
- \(a^{\frac 32}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac {1}{\sqrt a}\).
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