Question:

A particle of charge \( q \) and mass \( m \) moves in a circular orbit of radius \( r \) with angular speed \( \omega \). The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

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The ratio of magnetic moment to angular momentum depends on the charge and mass of the particle.
Updated On: Jan 12, 2026
  • \( \omega \) and \( q \)
  • \( q \) and \( m \)
  • \( \omega \) and \( m \)
  • \( q \) and \( r \)
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The Correct Option is B

Solution and Explanation

Step 1: Magnetic Moment and Angular Momentum.
For a charged particle moving in a circular orbit, the magnetic moment \( \mu \) is given by: \[ \mu = \frac{q v r}{2} \] where \( v = r \omega \). The angular momentum \( L \) is: \[ L = m r^2 \omega \] Thus, the ratio of the magnetic moment to angular momentum depends on \( q \) and \( m \).
Step 2: Conclusion.
The correct answer is (B), \( q \) and \( m \).
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