Question

A particle having a mass 0.5 kg is projected under gravity with a speed of 98 m/s at an angle of \( 60^\circ \). The magnitude of the change in momentum (in N-sec) of the particle after 10 seconds is:

• A. 0.5
• B. 49
• C. 98
• D. 490

Hint:

In projectile motion, use the initial and final velocities along the relevant direction to calculate the change in momentum.

Answer 1

The Correct Option is C

The change in momentum can be found using the formula: \[ \Delta p = m(v_f - v_i) \] where \( m = 0.5 \, \text{kg} \), initial velocity \( v_i = 98 \, \text{m/s} \), and final velocity \( v_f \) after 10 seconds can be calculated based on projectile motion. Using the time of flight and the motion under gravity, the change in momentum is 98 N-sec.
Final Answer: \[ \boxed{98} \]