Question

A particle executes SHM with a period of 6 s and amplitude of 3 cm. Its maximum speed in cm/s is:

• A. \( \pi \)
• B. \( 2\pi \)
• C. \( 3\pi \)
• D. 3

Hint:

The maximum speed in SHM is given by the product of the amplitude and the angular frequency \( \omega \), which depends on the period.

Answer 1

The Correct Option is B

The maximum speed \( v_{\text{max}} \) in SHM is given by: \[ v_{\text{max}} = A \cdot \omega \] Where:
- \( A = 3 \, \text{cm} \) is the amplitude,
- \( \omega = \frac{2\pi}{T} = \frac{2\pi}{6} \, \text{rad/s} \) is the angular frequency,
- \( T = 6 \, \text{s} \) is the period. Thus, \[ v_{\text{max}} = 3 \times \frac{2\pi}{6} = 2\pi \, \text{cm/s} \]