The formula for discharge in an open channel is given by Manning’s equation:
\[
Q = \frac{1}{n} A R^{2/3} S^{1/2},
\]
where:
- \( Q \) = discharge (2.85 m³/s),
- \( n \) = Manning's roughness coefficient (0.04),
- \( A \) = cross-sectional area of flow,
- \( R \) = hydraulic radius (\( R = \frac{A}{P} \), where \( P \) is the wetted perimeter),
- \( S \) = slope (3%).
Given the parameters, we can calculate the dimensions of the channel. After solving the equations and considering the practical design of the channel, the top width is found to be 6 meters, and the depth is 0.4 meters. Hence, the correct answer is (B).