Question:

A parabolic shaped grass-waterway is to be designed to carry a flow of 2.85 m³/s down the slope of 3%. The permissible velocity of water in the waterway is 1.78 m/s. If the freeboard depth is excluded, the most appropriate top width in m and depth in m, respectively are (Take Manning’s roughness coefficient = 0.04).

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When designing open channels, use Manning’s equation to determine the dimensions based on discharge, slope, and roughness coefficient. Adjust the design until the calculated discharge matches the required value.
Updated On: Nov 27, 2025
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The Correct Option is B

Solution and Explanation

The formula for discharge in an open channel is given by Manning’s equation:
\[ Q = \frac{1}{n} A R^{2/3} S^{1/2}, \]
where:
- \( Q \) = discharge (2.85 m³/s),
- \( n \) = Manning's roughness coefficient (0.04),
- \( A \) = cross-sectional area of flow,
- \( R \) = hydraulic radius (\( R = \frac{A}{P} \), where \( P \) is the wetted perimeter),
- \( S \) = slope (3%).
Given the parameters, we can calculate the dimensions of the channel. After solving the equations and considering the practical design of the channel, the top width is found to be 6 meters, and the depth is 0.4 meters. Hence, the correct answer is (B).
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