Step 1: Let the two-digit number be \(10a+b\), where \(a\) is the tens digit (\(1\leq a \leq 9\)) and \(b\) is the units digit (\(0\leq b \leq 9\)).
Step 2: The condition for "interesting" is
\[
a+b+ab = 10a+b.
\]
Simplify:
\[
ab + a + b = 10a + b ⇒ ab + a = 10a ⇒ ab = 9a.
\]
Step 3: If \(a=0\), not possible since the number is two-digit. For \(a \neq 0\), divide both sides by \(a\):
\[
b = 9.
\]
So all interesting numbers end with digit \(9\).
Step 4: Valid numbers are \(19, 29, 39, \dots, 99\). That is, 9 interesting numbers.
Step 5: Total numbers between 10 and 100 inclusive: \(91\) (from 10 to 100). Thus fraction
\[
\frac{9}{91}\approx 0.0989 \approx 0.099.
\]
This is approximately 0.099, which is closest to 0.1, but since the exact options provided do not match, the correct choice is \(\boxed{\text{None of the above}}\).