Question:
A movable mirror of Michelson’s interferometer is moved through a distance of 0.06 mm. If 200 fringes cross the field of view, the wavelength of light is:
A movable mirror of Michelson’s interferometer is moved through a distance of 0.06 mm. If 200 fringes cross the field of view, the wavelength of light is:
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The wavelength in Michelson’s interferometer is calculated using \( \lambda = \frac{2d}{N} \).
Updated On: Mar 26, 2025
- 6000 Å
- 4000 Å
- 8000 Å
- 3000 Å
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The Correct Option is B
Solution and Explanation
The fringe shift in Michelson’s interferometer is given by:
\[ \lambda = \frac{2d}{N} \] where:
- \( d = 0.06 \) mm = \( 60 \) μm
- \( N = 200 \) fringes
\[ \lambda = \frac{2 \times 60}{200} = 0.6 \mu m = 6000 \text{ Å} \]
\[ \lambda = \frac{2d}{N} \] where:
- \( d = 0.06 \) mm = \( 60 \) μm
- \( N = 200 \) fringes
\[ \lambda = \frac{2 \times 60}{200} = 0.6 \mu m = 6000 \text{ Å} \]
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