Let x be the price of single ticket
Return railway ticket = \(\frac{125x}{100}\)
5% of return ticket
= \(\frac{5}{100} \times \frac{125x}{100}\)
= \(\frac{25x}{400}\)
= \(\frac{x}{16}\)
Given,
\(\frac{125x}{100} + \frac{x}{16} = 84\)
Solving for x, we get
x=64
Therefore, the correct option is (A): Rs 64
List-I | List-II |
---|---|
(A) Confidence level | (I) Percentage of all possible samples that can be expected to include the true population parameter |
(B) Significance level | (III) The probability of making a wrong decision when the null hypothesis is true |
(C) Confidence interval | (II) Range that could be expected to contain the population parameter of interest |
(D) Standard error | (IV) The standard deviation of the sampling distribution of a statistic |