A mass of 0.5 kg moving with a speed of 1.5 m/s on a horizontal smooth surface, collides with a nearly weightless spring of force constant \( k = 50 \, \text{N/m} \). The maximum compression of the spring would be:
Show Hint
In problems involving springs, use energy conservation to relate kinetic and potential energies.
Step 1: Energy conservation.
The initial kinetic energy of the mass is converted into potential energy of the spring at maximum compression. The equation is:
\[
\frac{1}{2} m v^2 = \frac{1}{2} k x^2
\]
Step 2: Solving for \( x \).
Substituting the given values:
\[
\frac{1}{2} (0.5) (1.5)^2 = \frac{1}{2} (50) x^2
\]
Solving for \( x \), we get:
\[
x = 0.15 \, \text{m}
\]
Final Answer:
\[
\boxed{0.15 \, \text{m}}
\]