Question:

A mass of $0.5\, kg$ moving with a speed of $1.5\, m/ s$ on a horizontal smooth surface, collides with a nearly weightless spring of force constant $k = 50\, N/m$. The maximum compression of the spring would be

Updated On: Apr 28, 2024
  • $0.5\,m$
  • $0.15\,m$
  • $0.12\,m$
  • $1.5\,m$
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The Correct Option is B

Solution and Explanation

Apply law of conservation of energy, $\frac{1}{2}mv^{2}=\frac{1}{2} kx^{2}$
$\Rightarrow mv^{2}=kx^{2}$ or $0.5\times\left(1.5\right)^{2}=50\times x^{2}$
$\therefore x=0.15\,m$
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Concepts Used:

Conservation of Energy

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.

It also means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another. For instance, chemical energy is converted to kinetic energy when a stick of dynamite explodes.

So, mathematically we can represent the law of energy conservation as the following,

The amount of energy spent in a work = The amount of Energy gained in the related work

Now, the derivation of the energy conservation formula is as followed,

Ein − Eout = Δ Esys

We know that the net amount of energy which is transferred in or out of any system is mainly seen in the forms of heat (Q), mass (m) or work (W). Hence, on re-arranging the above equation, we get,

Ein − Eout = Q − W

Now, on dividing all the terms into both the sides of the equation by the mass of the system, the equation represents the law of conservation of energy on a unit mass basis, such as

Q − W = Δ u

Thus, the conservation of energy formula can be written as follows,

Q – W = dU / dt

Here,

Esys = Energy of the system as a whole

Ein = Incoming energy

Eout = Outgoing energy

E = Energy

Q = Heat

M = Mass

W = Work

T = Time