Question:

A man weighs $80\, kg$. He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $5 \,ms^{-2}$ What would be the reading on the scale? ($g = 10\, ms^{-2})$

Updated On: Jun 20, 2022
  • 800 N
  • 1200 N
  • Zero
  • 400 N
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The Correct Option is B

Solution and Explanation

When lift is moving upwards, it weighs more than actual weight of man by a factor of $m a .$
Mass of man $M=80\, kg$


Acceleration of lift, $a=5 \,m / s ^{2}$
When lift is moving upwards,
the reading of weighting scale will be equal to $R$.
The equation of motion gives
$R-m g=m a$
or $R=m g+m a=m(g+a)$
$\therefore R=80(10+5)$
$=80 \times 15=1200\, N$
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