The man has Rs. 480 in coins consisting of one-rupee, five-rupee, and ten-rupee coins, and the number of each type of coin is equal. Let the number of each type of coin be denoted by x. Therefore, we have:
- x coins of one-rupee = Rs. x
- x coins of five-rupees = Rs. 5x
- x coins of ten-rupees = Rs. 10x
The total value of all the coins is the sum of the values of each type:
Total Value = Rs. x + Rs. 5x + Rs. 10x = Rs. 16x
We know from the problem that the total value is Rs. 480, so we set up the equation:
16x = 480
Solving for x, we divide both sides by 16:
x = 480 / 16 = 30
This tells us there are 30 of each type of coin. Therefore, the total number of coins is:
Number of Coins = x + x + x = 3x = 3 × 30 = 90
Thus, the total number of coins the man has is 90.