A man bets on number 16 on a roulette wheel 14 times and loses each time. On the 15th spin, he does a quick calculation and finds out that the number 12 had appeared twice in the 14 spans and is therefore unable to decide whether to bet on 16 or 12 in the 15th spin Which will give him the best chance and what are the odds of winning on the bet that he takes? (Roulette has numbers 1 to 36).

Question

cdquestions Admin · Accepted Answer

Each spin is an independent event, and the result of the 15th spin is not influenced by the outcomes of the previous spins. The correct answer is (C) : 12,7:1

Answer

Answer

Answer

Answer

Either; 35:1

List-I	List-II (Adverbs)
(A) P(exactly 2 heads)	(I) \(\frac{1}{4}\)
(B) P(at least 1 head)	(II) \(1\)
(C) P(at most 2 heads)	(III) \(\frac{3}{4}\)
(D) P(exactly 1 head)	(IV) \(\frac{1}{2}\)

LIST-I(EVENT)	LIST-II(PROBABILITY)
(A) The sum of the number is greater than 11	(i) 0
(B) The sum of the number is 4 or less	(ii) 1/15
(C) The sum of the number is 4	(iii) 2/15
(D) The sum of the number is 4	(iv) 3/15

The Correct Option is C

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