Question

A magnetic field of 5 T is applied perpendicular to a coil with 5 turns. The induced emf in the coil is 10 V. The rate of change of magnetic flux is:

• A. \( 50 \, \text{Wb/s} \)
• B. \( 5 \, \text{Wb/s} \)
• C. \( 1 \, \text{Wb/s} \)
• D. \( 0.5 \, \text{Wb/s} \)

Hint:

The induced emf is proportional to the rate of change of magnetic flux through the coil.

Answer 1

The Correct Option is A

Step 1: Use Faraday's Law of Induction.
According to Faraday’s Law, the induced emf is given by: \[ \mathcal{E} = N \frac{d\Phi}{dt} \] where \( N \) is the number of turns, \( \Phi \) is the magnetic flux, and \( \frac{d\Phi}{dt} \) is the rate of change of magnetic flux.

Step 2: Calculate the rate of change of flux.
Substituting the given values: \[ 10 = 5 \times \frac{d\Phi}{dt} \quad \Rightarrow \quad \frac{d\Phi}{dt} = 2 \, \text{Wb/s} \]