Question:

A magnetic field intensity at the centre of a circular wire of radius 0.1 m carrying a current 0.2 A is:

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Always use the formula for the magnetic field at the center of a circular loop and remember to substitute values carefully.
Updated On: May 15, 2025
  • \( 2\pi \times 10^{-5} \, T \)
  • \( \pi \times 10^{-7} \, T \)
  • \( 10^{-7} \, T \)
  • \( 4\pi \times 10^{-7} \, T \)
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The Correct Option is D

Solution and Explanation

The magnetic field intensity at the centre of a circular loop is given by the formula: \[ B = \frac{\mu_0 I}{2r} \] where:
  • \( B \) is the magnetic field intensity,
  • \( \mu_0 = 4\pi \times 10^{-7} \, T \cdot m/A \) is the permeability of free space,
  • \( I = 0.2 \, A \) is the current, and
  • \( r = 0.1 \, m \) is the radius of the circular loop.
Substituting the given values into the formula: \[ B = \frac{4\pi \times 10^{-7} \times 0.2}{2 \times 0.1} = 4\pi \times 10^{-7} \, T \] Thus, the magnetic field intensity is \( 4\pi \times 10^{-7} \, T \).
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