Question:
A luminous body radiates energy at a rate $3.6 \times 10^{28}$ J/s, then loss of mass of the body per second is
A luminous body radiates energy at a rate $3.6 \times 10^{28}$ J/s, then loss of mass of the body per second is
Updated On: Apr 23, 2023
- $2 \times 10^3 \, kg / s$
- $3 \times 10^4 \, kg / s$
- $4 \times 10^{11} \, kg / s$
- $5 \times 10^5 \, kg / s$
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The Correct Option is C
Solution and Explanation
Energy and mass are related by the relation
$ E = mc^2$
Differentiating, we get
$ \frac{dE}{dt} = m \times [0] + c^2 \, \frac{dm}{dt}$
$\Rightarrow 3.6 \times 10^{28} = 9 \times 10^{16} \, \frac{dm}{dt}$
$\Rightarrow \frac{dm}{dt} = 4 \times 10^{11} \, kg/s$
$ E = mc^2$
Differentiating, we get
$ \frac{dE}{dt} = m \times [0] + c^2 \, \frac{dm}{dt}$
$\Rightarrow 3.6 \times 10^{28} = 9 \times 10^{16} \, \frac{dm}{dt}$
$\Rightarrow \frac{dm}{dt} = 4 \times 10^{11} \, kg/s$
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