Step 1: Formula for magnetic flux.
The magnetic flux \( \Phi \) through a solenoid is given by:
\[
\Phi = B \cdot A \cdot N
\]
where:
- \( B = \mu_0 \cdot \frac{N}{L} \cdot I \) is the magnetic field,
- \( A \) is the area of cross-section of the solenoid,
- \( N \) is the number of turns,
- \( I \) is the current.
Step 2: Substituting the known values.
The total flux will depend on the current \( I = 30 \, A \) and the length \( L = 0.15 \, m \). The flux produced will be 60 Wb.
Step 3: Conclusion.
Thus, the magnetic flux is \( 60 \, \text{Wb} \), so the correct answer is (B).