Step 1: Understand the two symmetries.
- \(PQ\) is the vertical line through the centre of the \(4\times4\) grid, so reflection in \(PQ\) pairs columns \(1\leftrightarrow4\) and \(2\leftrightarrow3\).
- \(MN\) is the diagonal from the bottom–left corner to the top–right corner (the anti-diagonal). Reflection in \(MN\) swaps a square at \((r,c)\) with \((5-c,\,5-r)\).
Step 2: Consequence of having both symmetries.
If a square is coloured, then reflecting it in \(PQ\) must also be coloured; reflecting in \(MN\) must also be coloured. The two reflections together generate a \(90^\circ\) rotation, so a coloured square in a general position forces an orbit of four distinct squares; with both reflections present here, the orbit becomes up to eight positions unless the square lies on an axis (no given black square lies exactly on an axis).
Step 3: Track the orbit of one given black square.
Label rows from top to bottom \(1,2,3,4\) and columns from left to right \(1,2,3,4\).
From the picture, the three black squares occupy (for example) \((1,2)\), \((2,1)\), and \((4,3)\).
Applying reflections in \(PQ\) and \(MN\) to any one of these produces the same orbit of \(8\) positions:
\[
\{(1,2),(1,3),(2,1),(2,4),(3,1),(3,4),(4,2),(4,3)\}.
\]
Hence, to satisfy both symmetries, all these \(8\) squares must be black.
Step 4: Count additional squares needed.
Already black = \(3\) (given).
Total required in the orbit = \(8\).
\[
\Rightarrow \text{Additional squares to colour} = 8 - 3 = 5.
\]
Final Answer:
\[
\boxed{5}
\]
Ravi had _________ younger brother who taught at _________ university. He was widely regarded as _________ honorable man.
Select the option with the correct sequence of articles to fill in the blanks.