0\(\%\) alcohol solution is mixed with 19\(\%\) alcohol solution to give 26\(\%\) alcohol solution.
\(\frac{w1}{w2}=\frac{(A2-Aavg)}{(Aavg-A1)}\)
\(=\frac{(40-26)}{(26-19)}\)
\(=\frac{14}{7}=\frac{2}{1}\)
So 2 parts of 19\(\%\) solution was mixed with 1 part of 40\(\%\) solution. This means that \(\frac{2}{3}^{rd}\) of the 40\(\%\) solution was replaced by 19\(\%\) solution. So the correct option is (A)