Given that A is three years younger than B, who is twice as old as C, we can establish the following relationships:
- Let C's age be \( x \).
- Then, B's age is \( 2x \). (since B is twice as old as C)
- And A's age is \( 2x - 3 \). (since A is three years younger than B)
According to the problem, the sum of their ages is 52:
\( (2x - 3) + 2x + x = 52 \)
Simplifying the equation:
\( 5x - 3 = 52 \)
Add 3 to both sides:
\( 5x = 55 \)
Divide by 5:
\( x = 11 \)
Now that we have \( x = 11 \), we can find B's age:
- B's current age is \( 2x = 2 \times 11 = 22 \).
To find B's age two years hence:
- The age of B in two years will be \( 22 + 2 = 24 \).
Therefore, B's age in two years will be 24 years.