Question:
A hollow insulated conduction sphere is given a positive charge of 10 $\mu$C. What will be the electric field at the centre of the sphere if its radius is 2 metres?
A hollow insulated conduction sphere is given a positive charge of 10 $\mu$C. What will be the electric field at the centre of the sphere if its radius is 2 metres?
Updated On: Apr 26, 2024
- Zero
- $5 \mu Cm^{-2}$
- $20 \mu Cm^{-2}$
- $8 \mu Cm^{-2}$
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Charge resides on the outer surface of a conducting hollow sphere of radius R. We consider a spherical surface of radius r < R. By Gauss theorem
$\int_{s}\vec{E.} \vec{d}s =\frac{1}{\varepsilon_{0}} \times$ charge enclosed or $ E\times4 \pi r^{2} =\frac{1}{\varepsilon_{0}} \times0 \, \Rightarrow\quad E=0\quad$
i.e electric field inside a hollow sphere is zero.
$\int_{s}\vec{E.} \vec{d}s =\frac{1}{\varepsilon_{0}} \times$ charge enclosed or $ E\times4 \pi r^{2} =\frac{1}{\varepsilon_{0}} \times0 \, \Rightarrow\quad E=0\quad$
i.e electric field inside a hollow sphere is zero.
Was this answer helpful?
1
0
Top Questions on Electric Field
- \(\sigma\) is the uniform surface charge density of a thin spherical shell of radius \(R\). The electric field at any point on the surface of the spherical shell is:
- JEE Main - 2024
- Physics
- Electric Field
- The distance between charges \(+q\) and \(-q\) is \(2l\) and between \(+2q\) and \(-2q\) is \(4l\). The electrostatic potential at point \(P\) at a distance \(r\) from center \(O\) is \(-\alpha \left[\frac{q}{r^2}\right] \times 10^9 \, \text{V}\), where the value of \(\alpha\) is ______.
(Use \(\frac{1}{4 \pi \epsilon_0} = 9 \times 10^9 \, \text{Nm}^2 \text{C}^{-2}\))
- JEE Main - 2024
- Physics
- Electric Field
- 1 tesla =
- AP POLYCET - 2024
- Physics
- Electric Field
- A thin glass rod is bent in a semicircle of radius R.A charge is non-uniformly distributed along the rod with a linear charge density \(\lambda=\lambda_0sin\theta\) (\(\lambda_0\) is a positive constant). The electric field at the center P of the semicircle is
- WBJEE - 2023
- Physics
- Electric Field
- When electric field is applied to the electrons in a conductor it starts
- JEE Main - 2023
- Physics
- Electric Field
View More Questions
Questions Asked in VITEEE exam
- Two identical blocks A and B, each of mass 'm' resting on a smooth floor are connected by a light spring of natural length L and spring constant K, with the spring at its natural length. A third identical block 'C' (mass m) moving with a speed v along the line joining A and B collides with A. the maximum compression in the spring is
- VITEEE - 2023
- work, energy and power
- Assertion :
The binding energy of the nucleus increases with the increase in atomic number.
Reason :
Heavier elements have a greater number of non-radioactive isotopes than radioactive isotopes. - The half-life of radioactive radon is 3.8 days. The time at the end of which \(\frac{1}{20}th\) of the Radon sample will remain undecayed is (given log10e=0.4343)
- Which element has more electron gain enthalpy among chalcogen group?
- VITEEE - 2022
- sulphur
- Coin is tossed till heads is obtained what is expectation of no. of coin tosses
- VITEEE - 2022
- Random Variables
View More Questions
Concepts Used:
Electric Field
Electric Field is the electric force experienced by a unit charge.
The electric force is calculated using the coulomb's law, whose formula is:
\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)
While substituting q2 as 1, electric field becomes:
\(E=k\dfrac{|q_{1}|}{r^{2}}\)
SI unit of Electric Field is V/m (Volt per meter).