A Gulab jamun, contains sugar syrup up to about 30% of its volume. Find approximately how much syrup would be found in 45 gulab jamuns, each shaped like a cylinder with two hemispherical ends with length 5 cm and diameter 2.8 cm (see the given figure). [Use \(\pi=\frac{22}{ 7}\)]
Solution and Explanation
It can be observed that
Radius (r) of cylindrical part = Radius (r) of hemispherical part = \(\frac{2.8}{2}=1.4\) cm
Length of each hemispherical part = Radius of hemispherical part = 1.4 cm
Length (h) of cylindrical part = 5 β 2 Γ Length of hemispherical part = 5 β 2 Γ 1.4 = 2.2 cm
Volume of one gulab jamun = Vol. of cylindrical part + 2 Γ Vol. of hemispherical part
\(= \pi r^2h+ 2 Γ (\frac{2}{3})\pi r^3\)
\(= 4.312\pi +(\frac{10.976}{3}) \pi\)
= 25.05 cm3
Volume of 45 gulab jamuns = 45Γ25.05 = 1,127.25 cm3
Volume of sugar syrup = 30% of volume
= 45Γ30% (25.05 cm3)
= 45Γ7.515 = 338.184 cm3
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Concepts Used:
Surface Area and Volume
Surface area and volume are two important concepts in geometry that are used to measure the size and shape of three-dimensional objects.
Surface area is the measure of the total area that the surface of an object covers. It is expressed in square units, such as square meters or square inches. To calculate the surface area of an object, we find the area of each face or surface and add them together. For example, the surface area of a cube is equal to six times the area of one of its faces.
Volume, on the other hand, is the measure of the amount of space that an object takes up. It is expressed in cubic units, such as cubic meters or cubic feet. To calculate the volume of an object, we measure the length, width, and height of the object and multiply these three dimensions together. For example, the volume of a cube is equal to the length of one of its edges cubed.
Surface area and volume are important in many fields, such as architecture, engineering, and manufacturing. For example, surface area is used to calculate the amount of material needed to cover an object, while volume is used to determine the amount of space that a container can hold. Understanding surface area and volume is also important in calculus and physics, where they are used to model the behavior of objects in three-dimensional space.